$A$ thermodynamic system is taken from state $A$ to $B$ along $ACB$ and is brought back to $A$ along $BDA$ as shown in the $PV$ diagram. The net work done during the complete cycle is given by the area

  • A
    $P_1ACBP_2P_1$
  • B
    $ACBB'A'A$
  • C
    $ACBDA$
  • D
    $ADBB'A'A$

Explore More

Similar Questions

The pressure and volume of a gas are changed as shown in the $P-V$ diagram in this figure. The temperature of the gas will ........

In the following figures $(a)$ to $(d)$,the variation of volume with change of pressure is shown. The gas is taken along the path $A B C D A$. The change in internal energy of the gas will be .......

The figure given below shows the variation in the internal energy $U$ with volume $V$ of $2.0 \text{ mole}$ of an ideal gas in a cyclic process $abcda$. The temperatures of the gas during the processes $ab$ and $cd$ are $500 \text{ K}$ and $300 \text{ K}$ respectively. The heat absorbed by the gas during the complete process is .... $J$. (Take $R = 8.3 \text{ J/mol-K}$ and $\ln 2 = 0.69$)

Difficult
View Solution

In the cyclic process shown on the $P-V$ diagram,the magnitude of the work done is

Difficult
View Solution

$A$ system goes from $A$ to $B$ via two processes $I$ and $II$ as shown in the figure. If $\Delta U_I$ and $\Delta U_{II}$ are the changes in internal energies in the processes $I$ and $II$ respectively,then:

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo