(C) Let $d_w$ and $d_o$ be the densities of water and oil respectively. The pressure at the bottom of the tank is given by $P = h_w d_w g + h_o d_o g$

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$\sqrt{920 \times 980} \, cm/s$

(C) Let $d_w$ and $d_o$ be the densities of water and oil respectively. The pressure at the bottom of the tank is given by $P = h_w d_w g + h_o d_o g$.We can find the equivalent height $h$ of a water column that exerts the same pressure at the bottom: $h d_w g = h_w d_w g + h_o d_o g$.Substituting the given values: $h = h_w + \frac{h_o d_o}{d_w} = 100 + \frac{400 \times 0.9}{1} = 100 + 360 = 460 \, cm$.According to Torricelli's theorem,the velocity of efflux $v$ is given by $v = \sqrt{2gh}$.Substituting the values: $v = \sqrt{2 \times 980 \times 460} = \sqrt{920 \times 980} \, cm/s$.

Class 11 Physics Fluid Mechanics and Surface Tension Velocity of Efflux and Torricelli's law

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$A$ tank is filled with water of density $1 \, g/cm^3$ and oil of density $0.9 \, g/cm^3$. The height of the water layer is $100 \, cm$ and the height of the oil layer is $400 \, cm$. If $g = 980 \, cm/s^2$,then the velocity of efflux from an opening in the bottom of the tank is

A
$\sqrt{900 \times 980} \, cm/s$
B
$\sqrt{1000 \times 980} \, cm/s$
C
$\sqrt{920 \times 980} \, cm/s$
D
$\sqrt{950 \times 980} \, cm/s$

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Fluid Mechanics and Surface Tension

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Velocity of Efflux and Torricelli's law

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$A$ tank is filled with water of density $1 \, g/cm^3$ and oil of density $0.9 \, g/cm^3$. The height of the water layer is $100 \, cm$ and the height of the oil layer is $400 \, cm$. If $g = 980 \, cm/s^2$,then the velocity of efflux from an opening in the bottom of the tank is

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The height of the water level in a tank of uniform cross-section is $5 \,m$. The volume of water leaked in $5 \,s$ through a hole of area $2.4 \,mm^2$ made at the bottom of the tank is (Assume the level of the water in the tank remains constant and acceleration due to gravity $= 10 \,ms^{-2}$).

$A$ tank is filled with water and two holes $A$ and $B$ are made in it. For getting the same range,the ratio of $h^{\prime}$ to $h$ is ..........

There is a hole of area $A_0$ at the bottom of a cylindrical vessel of cross-sectional area $A$. Water is filled up to a height $h$ and the water flows out in time $t$. If water is filled to a height $4h$,it will flow out in time equal to:

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