A tank can be filled with water by two pipes | vedclass

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Question

(D) Let the work done by pipe $A$ in $1$ minute be $a$ and by pipe $B$ be $b$.Given that $(a + b) = \frac{1}{36}$.In $30$ minutes,the part of the tank

Vedclass · Accepted Answer

$90 	ext{ minutes}$

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(D) Let the work done by pipe $A$ in $1$ minute be $a$ and by pipe $B$ be $b$.Given that $(a + b) = \frac{1}{36}$.In $30$ minutes,the part of the tank filled by both pipes is $30(a + b) = 30 	imes \frac{1}{36} = \frac{5}{6}$.The remaining part of the tank is $1 - \frac{5}{6} = \frac{1}{6}$.This remaining part is filled by pipe $A$ alone in $(40 - 30) = 10$ minutes.So,$10a = \frac{1}{6}$,which means $a = \frac{1}{60}$.Now,substitute $a$ in the first equation: $\frac{1}{60} + b = \frac{1}{36}$.$b = \frac{1}{36} - \frac{1}{60} = \frac{5 - 3}{180} = \frac{2}{180} = \frac{1}{90}$.Therefore,pipe $B$ alone can fill the tank in $90$ minutes.

$A$ tank can be filled with water by two pipes $A$ and $B$ together in $36$ minutes. If the pipe $B$ was closed after $30$ minutes,the tank is filled in $40$ minutes. The pipe $B$ can alone fill the tank in?

Similar Questions

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