A tank 3, m long,2, m wide and 1.5, m deep is | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Volume of the earth dug out from the tank $= (3 	imes 2 	imes 1.5) \, m^3 = 9 \, m^3$.The area of the field is $(22 	imes 14) \, m^2 = 308 \, m

Vedclass · Accepted Answer

$2.98$

Vedclass · Answer

(C) Volume of the earth dug out from the tank $= (3 	imes 2 	imes 1.5) \, m^3 = 9 \, m^3$.The area of the field is $(22 	imes 14) \, m^2 = 308 \, m^2$.The area of the tank is $(3 	imes 2) \, m^2 = 6 \, m^2$.The area over which the earth is spread $= (308 - 6) \, m^2 = 302 \, m^2$.Let the rise in the level of the field be $h$ meters.Volume of earth spread = Area $	imes$ height$9 = 302 	imes h$$h = \frac{9}{302} \, m$.To convert into $cm$,multiply by $100$:$h = \frac{9}{302} 	imes 100 \, cm = \frac{900}{302} \, cm \approx 2.98 \, cm$.

$A$ tank $3\, m$ long,$2\, m$ wide and $1.5\, m$ deep is dug in a field $22\, m$ long and $14\, m$ wide. If the earth dug out is evenly spread out over the field,the level of the field will rise by nearly (in $cm$)

Similar Questions

$A$ right circular cylinder has a height of $18 \, cm$ and a radius of $7 \, cm$. The cylinder is cut into three equal parts by $2$ cuts parallel to the base. What is the percentage increase in the total surface area (in $\%$)?

The length of the diagonal of a cube is $6 \text{ cm}$. The volume of the cube (in $\text{cm}^3$) is (in $\sqrt{3}$)

If a right circular cone of height $24\, cm$ has a volume of $1232\, cm^{3},$ then the area (in $cm^{2}$) of its curved surface is:

If the radius of a sphere is doubled,then its volume is increased by (in $\%$)

$A$ cylindrical iron rod is $70\, cm$ long. The diameter of its end portion is $2\, cm$. What is its weight,reckoning a $cm^3$ of iron to weigh $10\, grams$? (in $kg$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module