A system of three polarizers P_1, P_2, P_3 is | vedclass

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(A) When unpolarized light of intensity $I_0$ passes through the first polarizer $P_1$,the transmitted intensity is $I_1 = I_0/2$.The pass axis of $P_

Vedclass · Accepted Answer

$10.67$

Vedclass · Answer

(A) When unpolarized light of intensity $I_0$ passes through the first polarizer $P_1$,the transmitted intensity is $I_1 = I_0/2$.The pass axis of $P_3$ is crossed with respect to $P_1$,meaning the angle between their axes is $90^{\circ}$.The pass axis of $P_2$ is inclined at $60^{\circ}$ to the pass axis of $P_3$. Therefore,the angle between the pass axis of $P_2$ and $P_1$ is $90^{\circ} - 60^{\circ} = 30^{\circ}$.Using Malus' Law,the intensity transmitted through $P_2$ is $I_2 = I_1 \cos^2(30^{\circ}) = (I_0/2) 	imes (3/4) = 3I_0/8$.The angle between the pass axis of $P_3$ and $P_2$ is $60^{\circ}$.Using Malus' Law again,the final intensity transmitted through $P_3$ is $I = I_2 \cos^2(60^{\circ}) = (3I_0/8) 	imes (1/4) = 3I_0/32$.Thus,the ratio $(I_0/I) = 32/3 \approx 10.67$.

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