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(C) The coordinates of the centre of mass $(X_{cm}, Y_{cm})$ for a system of particles are given by:$X_{cm} = \frac{m_1 x_1 + m_2 x_2 + m_3 x_3}{m_1 +

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$(2, 2)$

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(C) The coordinates of the centre of mass $(X_{cm}, Y_{cm})$ for a system of particles are given by:$X_{cm} = \frac{m_1 x_1 + m_2 x_2 + m_3 x_3}{m_1 + m_2 + m_3}$$Y_{cm} = \frac{m_1 y_1 + m_2 y_2 + m_3 y_3}{m_1 + m_2 + m_3}$Given $m_1 = m_2 = m_3 = m$ and positions $(x_1, y_1) = (1, 1), (x_2, y_2) = (2, 2), (x_3, y_3) = (3, 3)$.$X_{cm} = \frac{m(1) + m(2) + m(3)}{m + m + m} = \frac{6m}{3m} = 2$$Y_{cm} = \frac{m(1) + m(2) + m(3)}{m + m + m} = \frac{6m}{3m} = 2$Thus,the centre of mass is at $(2, 2)$.

$A$ system consists of $3$ particles each of mass $m$ located at $(1, 1), (2, 2),$ and $(3, 3)$. The coordinates of the centre of mass are

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