A sweetseller has 420 kaju barfis and 130 bad | vedclass

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(D) To minimize the area of the tray,we need to maximize the number of barfis in each stack. This is equivalent to finding the Highest Common Factor $

Vedclass · Accepted Answer

$10$

Vedclass · Answer

(D) To minimize the area of the tray,we need to maximize the number of barfis in each stack. This is equivalent to finding the Highest Common Factor $(HCF)$ of $420$ and $130$.Using Euclid's division algorithm:$420 = 130 	imes 3 + 30$$130 = 30 	imes 4 + 10$$30 = 10 	imes 3 + 0$The $HCF$ of $420$ and $130$ is $10$.Therefore,the sweetseller can place $10$ barfis in each stack to minimize the area occupied on the tray.

$A$ sweetseller has $420$ kaju barfis and $130$ badam barfis. She wants to stack them in such a way that each stack has the same number,and they take up the least area of the tray. What is the number of barfis that can be placed in each stack for this purpose?

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