A suspended long metal wire is stretched a small distance $x$ by a load $W$ in newton suspended at the other end. Select the best answer out of the following

  • A

    The loss in potential energy of the load $W$ is equal to the gain in energy of the wire in stretching a length $x$

  • B

    The energy stored in the wire can be calculated from the area between the force extension graph and the extension axis

  • C

    The energy per unit volume stored in the wire $ = \frac{1}{2}Wx$

  • D

    None of the above

Similar Questions

What is called elastic energy density ? Write its formula and dimensional formula.

The length of a rod is $20\, cm$ and area of cross-section $2\,c{m^2}$. The Young's modulus of the material of wire is $1.4 \times {10^{11}}\,N/{m^2}$. If the rod is compressed by $5\, kg-wt$ along its length, then increase in the energy of the rod in joules will be

A wire is suspended by one end. At the other end a weight equivalent to $20\, N$ force is applied. If the increase in length is $1.0\, mm$, the increase in energy of the wire will be .......  $joule$

The work per unit volume to stretch the length by $1\%$ of a wire with cross sectional area of $1\,m{m^2}$ will be. $[Y = 9 \times {10^{11}}\,N/{m^2}]$

Determine the elastic potential energy stored in stretched wire.