(B) Let the first part be $₹ x$. Then the second part is $₹ (2800 - x)$.Since the simple interest on both parts is equal,we use the formula $SI = \fra

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(B) Let the first part be $₹ x$. Then the second part is $₹ (2800 - x)$.Since the simple interest on both parts is equal,we use the formula $SI = \frac{P \times R \times T}{100}$.$\frac{x \times 9 \times 5}{100} = \frac{(2800 - x) \times 10 \times 6}{100}$$45x = (2800 - x) \times 60$Dividing both sides by $15$:$3x = (2800 - x) \times 4$$3x = 11200 - 4x$$7x = 11200$$x = 1600$Therefore,the first part is $₹ 1600$ and the second part is $2800 - 1600 = ₹ 1200$.

Competitive Quantitative Aptitude Interest Simple Interest

Medium

$A$ sum of ₹ $2800$ is divided into two parts in such a way that the interest on both the parts is equal. If the first part is lent at $9 \% \text{ p.a.}$ for $5 \text{ years}$ and the second part is for $6 \text{ years}$ at $10 \% \text{ p.a.}$,find the two sums.

A
₹ $1800$,₹ $1000$
B
₹ $1600$,₹ $1200$
C
₹ $1400$,₹ $1400$
D
₹ $1300$,₹ $1500$

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Quantitative Aptitude Questions

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Interest

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Simple Interest

The simple interest on a sum of money is $\frac{1}{9}$ of the principal and the number of years is equal to the rate per cent per annum. The rate per cent per annum is equal to

Medium

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₹ $800$ becomes ₹ $956$ in $3$ $years$ at a certain rate of simple interest. If the rate of interest is increased by $4 \%,$ what amount (in ₹) will ₹ $800$ become in $3$ $years?$

Medium

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Mrs. Sushma lent out an amount of $Rs. 3000$ at $4 \%$ p.a. and some other amount at $5 \%$ p.a. If at the end of the year she received $Rs. 138$ as total interest,what amount (in $Rs.$) did she lend out at $5 \%$ p.a.?

Medium

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If $A$ borrowed $₹P$ at $x\%$ and $B$ borrowed $₹Q$ $(Q > P)$ at $y\%$ per annum at simple interest at the same time,then the amount of their debts will be equal after:

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$A$ person invested $\frac{2}{3}$ of his capital at $3 \%$,$\frac{1}{6}$ at $6 \%$,and the remainder at $12 \%$. If his annual income is $₹ 25$,then the total capital (in $₹$) is:

Medium

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$A$ sum of ₹ $2800$ is divided into two parts in such a way that the interest on both the parts is equal. If the first part is lent at $9 \% \text{ p.a.}$ for $5 \text{ years}$ and the second part is for $6 \text{ years}$ at $10 \% \text{ p.a.}$,find the two sums.

Similar Questions

The simple interest on a sum of money is $\frac{1}{9}$ of the principal and the number of years is equal to the rate per cent per annum. The rate per cent per annum is equal to

₹ $800$ becomes ₹ $956$ in $3$ $years$ at a certain rate of simple interest. If the rate of interest is increased by $4 \%,$ what amount (in ₹) will ₹ $800$ become in $3$ $years?$

Mrs. Sushma lent out an amount of $Rs. 3000$ at $4 \%$ p.a. and some other amount at $5 \%$ p.a. If at the end of the year she received $Rs. 138$ as total interest,what amount (in $Rs.$) did she lend out at $5 \%$ p.a.?

If $A$ borrowed $₹P$ at $x\%$ and $B$ borrowed $₹Q$ $(Q > P)$ at $y\%$ per annum at simple interest at the same time,then the amount of their debts will be equal after:

$A$ person invested $\frac{2}{3}$ of his capital at $3 \%$,$\frac{1}{6}$ at $6 \%$,and the remainder at $12 \%$. If his annual income is $₹ 25$,then the total capital (in $₹$) is:

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