A substance undergoes first-order decompositi | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) For parallel first-order reactions,the percentage distribution of products is determined by the ratio of their respective rate constants to the to

Vedclass · Accepted Answer

$76.83\% \ B$ and $23.17\% \ C$

Vedclass · Answer

(D) For parallel first-order reactions,the percentage distribution of products is determined by the ratio of their respective rate constants to the total rate constant.$\% 	ext{ distribution of } B = \frac{k_1}{k_1 + k_2} 	imes 100$Given $k_1 = 1.26 	imes 10^{-4} \ s^{-1}$ and $k_2 = 0.38 	imes 10^{-4} \ s^{-1}$:$\% 	ext{ of } B = \frac{1.26 	imes 10^{-4}}{1.26 	imes 10^{-4} + 0.38 	imes 10^{-4}} 	imes 100 = \frac{1.26}{1.64} 	imes 100 \approx 76.83\%$$\% 	ext{ of } C = 100 - 76.83\% = 23.17\%$Thus,the percentage distribution is $76.83\% \ B$ and $23.17\% \ C$.

$A$ substance undergoes first-order decomposition. The decomposition follows two parallel first-order reactions as:
$A \xrightarrow{k_1} B$ $k_1 = 1.26 \times 10^{-4} \ s^{-1}$
$A \xrightarrow{k_2} C$ $k_2 = 3.8 \times 10^{-5} \ s^{-1}$
The percentage distribution of $B$ and $C$ are:

Similar Questions

If $r = k[A]^2[B]$ is the rate law equation for the reaction $A + B \rightarrow C$,at $[A] = 1 \ M$ and $[B] = 0.2 \ M$,calculate the rate of reaction if the rate constant is $6.25 \ M^{-2} \ s^{-1}$. (in $M \ s^{-1}$)

What is a pseudo first order reaction? Give an example of a pseudo first order reaction.

Which one of the following statements for the order of a reaction is incorrect?

The temperature coefficient of most reactions lies between $.......$.

The reaction $2 A + B + C \longrightarrow D + E$ is found to be first order in $A$,second order in $B$,and zero order in $C$. What is the effect of increasing the concentration of all reactants twice?

Vedclass Test Series

Exam Paper Generator

Online Exam Module

$A$ substance undergoes first-order decomposition. The decomposition follows two parallel first-order reactions as:$A \xrightarrow{k_1} B$ $k_1 = 1.26 \times 10^{-4} \ s^{-1}$$A \xrightarrow{k_2} C$ $k_2 = 3.8 \times 10^{-5} \ s^{-1}$The percentage distribution of $B$ and $C$ are: