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(C) To verify Ohm's law $(V=IR)$,we need to measure the voltage across the test resistor $R_T$ and the current flowing through it.$1$. $A$ voltmeter i

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(C) To verify Ohm's law $(V=IR)$,we need to measure the voltage across the test resistor $R_T$ and the current flowing through it.$1$. $A$ voltmeter is connected in parallel to the resistor. To convert a galvanometer into a voltmeter,a very high resistance must be connected in series with it. Here,$R_1=10\,M\,\Omega$ is a very high resistance,so $G_1$ in series with $R_1$ acts as a voltmeter.$2$. An ammeter is connected in series with the resistor. To convert a galvanometer into an ammeter,a very low resistance must be connected in parallel with it. Here,$R_2=0.001\,\Omega$ is a very low resistance,so $G_2$ in parallel with $R_2$ acts as an ammeter.$3$. In circuit $C$,$G_1$ is in series with $R_1$ (forming a voltmeter) and this combination is in parallel with $R_T$. $G_2$ is in parallel with $R_2$ (forming an ammeter) and this combination is in series with $R_T$. This is the correct configuration for verifying Ohm's law.

$A$ student is provided with a variable voltage source $V$,a test resistor $R_T=10\,\Omega$,two identical galvanometers $G_1$ and $G_2$,and two additional resistors,$R_1=10\,M\,\Omega$ and $R_2=0.001\,\Omega$. For conducting an experiment to verify Ohm's law,the most suitable circuit is:

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