(C) When a battery is being charged,the terminal voltage $V$ is given by the formula: $V = E + Ir$,where $E$ is the $EMF$ of the battery,$I$ is the ch

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(C) When a battery is being charged,the terminal voltage $V$ is given by the formula: $V = E + Ir$,where $E$ is the $EMF$ of the battery,$I$ is the charging current,and $r$ is the internal resistance.Given:Terminal voltage $V = 12.5 \text{ V}$Charging current $I = 0.5 \text{ A}$Internal resistance $r = 1 \ \Omega$Substituting the values into the equation:$12.5 = E + (0.5 \times 1)$$12.5 = E + 0.5$$E = 12.5 - 0.5$$E = 12 \text{ V}$Therefore,the $EMF$ of the storage battery is $12 \text{ V}$.

Class 12 Physics Current Electricity Electric Cells and Combination of cells in Series and Parallel

Medium

$A$ storage battery is connected to a charger for charging with a voltage of $12.5 \text{ V}$. The internal resistance of the storage battery is $1 \ \Omega$. When the charging current is $0.5 \text{ A}$,the $EMF$ of the storage battery is: ............... $\text{volts}$

A
$13$
B
$12.5$
C
$12$
D
$11.5$

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Class 12

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Current Electricity

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Electric Cells and Combination of cells in Series and Parallel

The number of dry cells,each of $e.m.f.$ $1.5\,V$ and internal resistance $0.5\,\Omega$,that must be joined in series with a resistance of $20\,\Omega$ so as to send a current of $0.6\,A$ through the circuit is:

Medium

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In the network shown,the potential difference between $A$ and $B$ is ................. $V$ $(R = r_1 = r_2 = r_3 = 1 \Omega, E_1 = 3 \, V, E_2 = 2 \, V, E_3 = 1 \, V)$.

Medium

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Four cells,each of emf $E$ and internal resistance $r$,are connected in series across an external resistance $R$. By mistake,one of the cells is connected in reverse. Then the current in the external circuit is

MediumWBJEE 2014

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In the given diagram,an ideal voltmeter $V$ reads $1.45\,V$. Then the relation between $r_1$ and $r_2$ is:

Difficult

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Two identical cells each of emf $1.5 \,V$ are connected in parallel across an external resistance formed by two $20 \,\Omega$ resistors connected in parallel. $A$ voltmeter connected in the circuit measures $1.2 \,V$. The internal resistance of each cell is ................. $\Omega$.

DifficultJEE MAIN 2022

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$A$ storage battery is connected to a charger for charging with a voltage of $12.5 \text{ V}$. The internal resistance of the storage battery is $1 \ \Omega$. When the charging current is $0.5 \text{ A}$,the $EMF$ of the storage battery is: ............... $\text{volts}$

Similar Questions

The number of dry cells,each of $e.m.f.$ $1.5\,V$ and internal resistance $0.5\,\Omega$,that must be joined in series with a resistance of $20\,\Omega$ so as to send a current of $0.6\,A$ through the circuit is:

In the network shown,the potential difference between $A$ and $B$ is ................. $V$ $(R = r_1 = r_2 = r_3 = 1 \Omega, E_1 = 3 \, V, E_2 = 2 \, V, E_3 = 1 \, V)$.

Four cells,each of emf $E$ and internal resistance $r$,are connected in series across an external resistance $R$. By mistake,one of the cells is connected in reverse. Then the current in the external circuit is

In the given diagram,an ideal voltmeter $V$ reads $1.45\,V$. Then the relation between $r_1$ and $r_2$ is:

Two identical cells each of emf $1.5 \,V$ are connected in parallel across an external resistance formed by two $20 \,\Omega$ resistors connected in parallel. $A$ voltmeter connected in the circuit measures $1.2 \,V$. The internal resistance of each cell is ................. $\Omega$.

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