A stone is projected from a point on the grou | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(d)

$2 h=\frac{u_y^2}{2 g}$

or $u_y=2(\sqrt{g} h)$

$\operatorname{Now}\left(t_2-t_1\right) u_x=t_2 v_x$ or $\frac{v_x}{u_x}=\frac{t_2-t_1}{t_

Vedclass · Accepted Answer

$\frac{2}{\sqrt{2}+1}$

Vedclass · Answer

(d)

$2 h=\frac{u_y^2}{2 g}$

or $u_y=2(\sqrt{g} h)$

$\operatorname{Now}\left(t_2-t_1\right) u_x=t_2 v_x$ or $\frac{v_x}{u_x}=\frac{t_2-t_1}{t_2}........(i)$

Further $h=u_y t-\frac{1}{2}(g t)^2$

or $g t^2-2 u_y t+h=0$

or $g t^2-4(\sqrt{g h}) t+2 h=0$

$t_1= \frac{4 \sqrt{g h}-\sqrt{16 g h-8 g h}}{2 g}=(2-\sqrt{2})\left(\frac{\sqrt{h}}{g}\right)$

Substituting in Eq. (i) we have,

$\frac{v_x}{u_x}=\frac{2}{(\sqrt{2})+1}$

Similar Questions

A body is projected at such an angle that the horizontal range is three times the greatest height. The angle of projection is

Two projectiles $A$ and $B$ are thrown with the same speed but angles are $40^{\circ}$ and $50^{\circ}$ with the horizontal. Then

A particle is projected with a velocity of $30\,m / s$, at an angle of $\theta_0=\tan ^{-1}\left(\frac{3}{4}\right)$ After $1\,s$, the particle is moving at an angle $\theta$ to the horizontal, where $\tan \theta$ will be equal to $\left(g=10\,m / s ^2\right)$

Balls $A$ and $B$ are thrown from two points lying on the same horizontal plane separated by a distance $120\,m$. Which of the following statement$(s)$ is/are correct.

A bullet is fired from a cannon with velocity $500 \,m/s$. If the angle of projection is ${15^o}$ and $g = 10m/{s^2}$. Then the range is