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(C) Given: Initial velocity of the balloon (and thus the stone) $u = 12 \, m/s$ (downward).Acceleration due to gravity $g = 9.8 \, m/s^2$ (downward).T

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$610$

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(C) Given: Initial velocity of the balloon (and thus the stone) $u = 12 \, m/s$ (downward).Acceleration due to gravity $g = 9.8 \, m/s^2$ (downward).Time $t = 10 \, s$.Since the stone is released from a descending balloon,its initial velocity is in the direction of motion (downward).Taking the downward direction as positive,the displacement $s$ is given by the kinematic equation:$s = ut + \frac{1}{2}gt^2$Substituting the values:$s = (12 \, m/s)(10 \, s) + \frac{1}{2}(9.8 \, m/s^2)(10 \, s)^2$$s = 120 + 0.5 	imes 9.8 	imes 100$$s = 120 + 490$$s = 610 \, m$.Therefore,the displacement of the stone after $10 \, s$ is $610 \, m$.

$A$ stone falls from a balloon that is descending at a uniform rate of $12 \, m/s$. The displacement of the stone from the point of release after $10 \, s$ is.......$m$ $(g = 9.8 \, m/s^2)$

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