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(A) The power consumed by the lamp is given by $P = V_{rms} 	imes I_{rms}$.Given $P = 100\,W$ and $V_{rms} = 200\,V$.Therefore,the root mean square c

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$0.707$

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(A) The power consumed by the lamp is given by $P = V_{rms} 	imes I_{rms}$.Given $P = 100\,W$ and $V_{rms} = 200\,V$.Therefore,the root mean square current $I_{rms} = \frac{P}{V_{rms}} = \frac{100}{200} = 0.5\,A$.The peak current $I_{peak}$ is related to the $RMS$ current by the formula $I_{peak} = I_{rms} 	imes \sqrt{2}$.Substituting the value of $I_{rms}$,we get $I_{peak} = 0.5 	imes \sqrt{2} = \frac{\sqrt{2}}{2} = \frac{1}{\sqrt{2}} \approx 0.707\,A$.

$A$ standard filament lamp consumes $100\,W$ when connected to $200\,V$ $AC$ mains supply. The peak current through the bulb will be $........\,A$.

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