A square wire loop of side 10.0 , cm is place | vedclass

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(D) The area of the square loop is $A = (10.0 \, cm)^2 = (0.1 \, m)^2 = 0.01 \, m^2.$The initial magnetic flux is $\phi_i = B \cdot A = 20 \, T 	imes

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$20$

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(D) The area of the square loop is $A = (10.0 \, cm)^2 = (0.1 \, m)^2 = 0.01 \, m^2.$The initial magnetic flux is $\phi_i = B \cdot A = 20 \, T 	imes 0.01 \, m^2 = 0.2 \, Wb.$The final magnetic flux is $\phi_f = 0 \, Wb$ as the field decreases to zero.The induced electromotive force $(EMF)$ is given by Faraday's Law: $|e| = |\frac{\Delta \phi}{\Delta t}|.$Given that the bulb glows with full brightness at $e = 10 \, V$,we have:$10 = \frac{|0 - 0.2|}{\Delta t}$$10 = \frac{0.2}{\Delta t}$$\Delta t = \frac{0.2}{10} = 0.02 \, s.$Converting to milliseconds: $\Delta t = 0.02 	imes 1000 \, ms = 20 \, ms.$

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