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(A) The induced electromotive force $(EMF)$ is given by Faraday's law: $e = -\frac{\Delta \phi}{\Delta t}$.For the bulb to shine with full brightness,

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$20$

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(A) The induced electromotive force $(EMF)$ is given by Faraday's law: $e = -\frac{\Delta \phi}{\Delta t}$.For the bulb to shine with full brightness,the induced $EMF$ must be equal to the rated voltage of the bulb,so $|e| = 10 \, V$.The change in magnetic flux $\Delta \phi$ is $\phi_i - \phi_f = B \cdot A - 0 = B \cdot A$.The area of the square loop is $A = (10.0 \, cm)^2 = (0.1 \, m)^2 = 0.01 \, m^2$.The initial magnetic flux is $\phi_i = B \cdot A = 20 \, T 	imes 0.01 \, m^2 = 0.2 \, Wb$.Using the formula $\Delta t = \frac{|\Delta \phi|}{|e|} = \frac{0.2 \, Wb}{10 \, V} = 0.02 \, s$.Converting to milliseconds: $0.02 \, s = 0.02 	imes 1000 \, ms = 20 \, ms$.

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