$A$ square loop is carrying a steady current $I$ and the magnitude of its magnetic dipole moment is $m$. If this square loop is changed to a circular loop and it carries the same current,the magnitude of the magnetic dipole moment of the circular loop will be
- A$\frac{m}{\pi}$
- B$\frac{3m}{\pi}$
- C$\frac{4m}{\pi}$
- D$\frac{2m}{\pi}$
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