$A$ spherical balloon is being inflated at the rate of $35 \, cm^3/min$. The rate of increase in the surface area (in $cm^2/min$) of the balloon when its diameter is $14 \, cm$,is

  • A
    $10$
  • B
    $\sqrt{10}$
  • C
    $100$
  • D
    $10\sqrt{10}$

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