A source of frequency f is emitting sound wav | vedclass

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Question

(A) The velocity of sound in a gaseous medium is given by $v = \sqrt{\frac{\gamma RT}{M}}$,which implies $v \propto \sqrt{T}$.Since the temperature $T

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wavelength of the sound wave increases

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(A) The velocity of sound in a gaseous medium is given by $v = \sqrt{\frac{\gamma RT}{M}}$,which implies $v \propto \sqrt{T}$.Since the temperature $T$ increases,the speed of sound $v$ also increases.The relationship between speed,frequency,and wavelength is $v = f \lambda$.Since the frequency $f$ is a characteristic of the source,it remains constant regardless of the medium's temperature.Therefore,$\lambda = \frac{v}{f}$. Since $v$ increases and $f$ is constant,the wavelength $\lambda$ must increase.Thus,the correct option is $(A)$.

Column-$I$	Column-$II$
$(a)$ Transverse wave through a steel rod	$(i)$ $\sqrt{B + \frac{4}{3} \frac{\eta}{\rho}}$
$(b)$ Longitudinal waves in earth's crust	$(ii)$ $\sqrt{\frac{\eta}{\rho}}$
$(c)$ Longitudinal waves through a steel rod	$(iii)$ $\sqrt{\frac{2 \pi T}{g \lambda}}$
$(d)$ Ripples	$(iv)$ $\sqrt{\frac{Y}{\rho}}$

$A$ source of frequency $f$ is emitting sound waves. If the temperature of the medium increases,then

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