$A$ solution of sodium in liquid ammonia is blue in colour due to

  • A
    the presence of ions $Na^{+}$
  • B
    the presence of ammoniated electron
  • C
    the formation of $NaNH_2$
  • D
    the formation of sodium hydride

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The incorrect statement regarding the above reactions is:
$Al_{(metal)} \xrightarrow[HCl]{(aq.)} 'X' + \text{Gas } 'P'$
$Al_{(metal)} \xrightarrow[NaOH (aq.)]{+ H_2O} 'Y' + \text{Gas } 'Q'$

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