A solution of Ph_3CCO_2H in concentrated H_2S | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) When $Ph_3CCO_2H$ is dissolved in concentrated $H_2SO_4$,it undergoes protonation followed by the loss of $CO$ to form a stable triphenylmethyl ca

Vedclass · Accepted Answer

$Ph_3COCH_3$

Vedclass · Answer

(C) When $Ph_3CCO_2H$ is dissolved in concentrated $H_2SO_4$,it undergoes protonation followed by the loss of $CO$ to form a stable triphenylmethyl carbocation $(Ph_3C^+)$.When this solution is poured into methanol $(CH_3OH)$,the methanol acts as a nucleophile and attacks the $Ph_3C^+$ carbocation.This results in the formation of methyl triphenylmethyl ether,which is $Ph_3COCH_3$ (also written as $Ph_3C-O-CH_3$).Therefore,the product $(X)$ is $Ph_3COCH_3$.

$A$ solution of $Ph_3CCO_2H$ in concentrated $H_2SO_4$ gives $(X)$ when poured into methanol. $X$ is

Similar Questions

Which reagent is used for the electrophilic aromatic bromination of methyl phenyl ether (anisole)?

Which of the following compounds on boiling with $KMnO_4$ (alk.) and subsequent acidification will not give benzoic acid?

Which of the following ethers is formed from the reaction of an alcohol with diazomethane?

$C_2H_5-Br + CH_3ONa \to A \xrightarrow[{(cold)}]{{HI}} B,$ product $B$ is

The reaction given below is known as:
$C_2H_5ONa + IC_2H_5 \xrightarrow{} C_2H_5OC_2H_5 + NaI$

Vedclass Test Series

Exam Paper Generator

Online Exam Module