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(C) During electrolysis,the cation with the highest standard reduction potential is reduced first at the cathode. Comparing the given reduction potent

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$Ag, Hg, Cu$

Vedclass · Answer

(C) During electrolysis,the cation with the highest standard reduction potential is reduced first at the cathode. Comparing the given reduction potentials: $E^0_{Ag^{+}/Ag} (+0.80 \ V) > E^0_{Hg_2^{2+}/Hg} (+0.79 \ V) > E^0_{Cu^{2+}/Cu} (+0.34 \ V) > E^0_{Mg^{2+}/Mg} (-2.37 \ V)$. Therefore,the order of deposition is $Ag$,then $Hg$,then $Cu$. $Mg^{2+}$ ions are not reduced because the reduction of water $(2H_2O + 2e^- \rightarrow H_2 + 2OH^-)$ occurs at a more positive potential than the reduction of $Mg^{2+}$ in an aqueous solution. Thus,the sequence of deposition is $Ag, Hg, Cu$.

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