A soap bubble assumes a spherical surface. Wh | vedclass

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(C) For a soap bubble, the excess pressure inside is given by $\Delta P = P_{in} - P_{out} = \frac{4T}{R}$, where $T$ is the surface tension and $R$ i

Vedclass · Accepted Answer

The pressure of air inside the bubble is less than the atmospheric pressure; that is why the atmospheric pressure has compressed it equally from all sides to give it a spherical shape.

Vedclass · Answer

(C) For a soap bubble, the excess pressure inside is given by $\Delta P = P_{in} - P_{out} = \frac{4T}{R}$, where $T$ is the surface tension and $R$ is the radius of the bubble. This implies that $P_{in} = P_{out} + \frac{4T}{R}$. Since $\frac{4T}{R} > 0$, the pressure inside the bubble is always greater than the atmospheric pressure. Therefore, statement $(C)$ is wrong because it incorrectly claims that the internal pressure is less than the atmospheric pressure.

$A$ soap bubble assumes a spherical surface. Which of the following statements is wrong?

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