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(B) When a small spherical ball is dropped into a viscous liquid,it initially accelerates due to gravity. As its velocity increases,the viscous drag f

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Curve $B$

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(B) When a small spherical ball is dropped into a viscous liquid,it initially accelerates due to gravity. As its velocity increases,the viscous drag force (which is proportional to velocity) also increases. According to Stokes' Law,the net force acting on the ball is $F_{net} = mg - F_v - F_b$,where $mg$ is the weight,$F_v$ is the viscous drag,and $F_b$ is the buoyant force. As the velocity increases,the viscous drag $F_v$ increases until the net force becomes zero $(F_{net} = 0)$. At this point,the ball attains a constant velocity known as the terminal velocity. The velocity-time graph should show an initial increase in velocity followed by a gradual approach to a constant value. Curve $B$ represents this behavior,where the slope decreases as the velocity approaches the terminal velocity.

$A$ small spherical solid ball is dropped from a great height in a viscous liquid. Its journey in the liquid is best described in the diagram given below by the

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