A small source of sound moves on a circle as | vedclass

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(B) According to the Doppler effect,the apparent frequency $n'$ is given by $n' = n \left( \frac{v}{v - v_s \cos 	heta} ight)$,where $v$ is the spe

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$n_2 > n_3 > n_1$

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(B) According to the Doppler effect,the apparent frequency $n'$ is given by $n' = n \left( \frac{v}{v - v_s \cos 	heta} ight)$,where $v$ is the speed of sound,$v_s$ is the speed of the source,and $	heta$ is the angle between the velocity vector of the source and the line joining the source to the observer.$1$. At point $A$,the source is moving away from the observer. The component of velocity along the line of sight is directed away,so the apparent frequency $n_1 $2$. At point $B$,the source is moving towards the observer. The component of velocity along the line of sight is directed towards the observer,so the apparent frequency $n_2 > n$.$3$. At point $C$,the velocity vector of the source is perpendicular to the line joining the source to the observer. Thus,the radial component of velocity is zero,and the apparent frequency $n_3 = n$.Comparing these,we get $n_2 > n_3 > n_1$.

$A$ small source of sound moves on a circle as shown in the figure and an observer is standing at $O$. Let $n_1, n_2$ and $n_3$ be the frequencies heard when the source is at $A, B$ and $C$ respectively. Then

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