$A$ small circular loop of conducting wire has radius $a$ and carries current $I$. It is placed in a uniform magnetic field $B$ perpendicular to its plane such that when rotated slightly about its diameter and released,it starts performing simple harmonic motion of time period $T$. If the mass of the loop is $m$,then find the expression for $T$.

  • A
    $T=\sqrt{\frac{\pi m}{2 IB}}$
  • B
    $T=\sqrt{\frac{2 \pi m}{IB}}$
  • C
    $T=\sqrt{\frac{\pi m}{IB}}$
  • D
    $T=\sqrt{\frac{2 m}{IB}}$

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