A sinusoidal carrier voltage is amplitude mod | vedclass

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(B) Given,maximum amplitude $A_{max} = A_c + A_m = 120 \, V$ and minimum amplitude $A_{min} = A_c - A_m = 80 \, V$.Adding these two equations: $2A_c =

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$10$

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(B) Given,maximum amplitude $A_{max} = A_c + A_m = 120 \, V$ and minimum amplitude $A_{min} = A_c - A_m = 80 \, V$.Adding these two equations: $2A_c = 200 \, V \implies A_c = 100 \, V$.Subtracting these two equations: $2A_m = 40 \, V \implies A_m = 20 \, V$.The modulation index $\mu = \frac{A_m}{A_c} = \frac{20}{100} = 0.2$.The amplitude of each sideband is given by $\frac{\mu A_c}{2}$.Substituting the values: $	ext{Amplitude} = \frac{0.2 	imes 100}{2} = \frac{20}{2} = 10 \, V$.

$A$ sinusoidal carrier voltage is amplitude modulated. The resultant amplitude modulated wave has maximum and minimum amplitude of $120 \, V$ and $80 \, V$ respectively. The amplitude of each sideband is $.......... \, V$.

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