$A$ simple pendulum with an iron bob has a time period $T$. The bob is now immersed in a non-viscous liquid and oscillated. If the density of the liquid is $\frac{1}{12}$th that of iron,then the new time period will be:

  • A
    $T \sqrt{\frac{8}{7}}$
  • B
    $T \sqrt{\frac{12}{13}}$
  • C
    $T \sqrt{\frac{12}{11}}$
  • D
    $T \sqrt{\frac{6}{5}}$

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