A simple pendulum with a bob of mass $m = 1\ kg$ , charge $q = 5\mu C$ and string length $l = 1\ m$ is given a horizontal velocity $u$ in a uniform electric field $E = 2 × 10^6\ V/m$ at its bottom most point $A$ , as shown in figure. It is given a speed $u$ such that the particle leave the circular path at its topmost point $C$ . Find the speed $u$ . (Take $g = 10\ m/s^2$ )

822-285

  • A

    $\sqrt {40} \,m/s$

  • B

    $\sqrt {50} \,m/s$

  • C

    $\sqrt {35} \,m/s$

  • D

    None of these

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