A simple pendulum has a time period t. Its ti | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The time period of a simple pendulum is given by $T = 2\pi \sqrt{\frac{l}{g_{eff}}}$.Initially,the effective acceleration due to gravity is $g = 9

Vedclass · Accepted Answer

$t \sqrt{\frac{9.8}{12.8}}$

Vedclass · Answer

(A) The time period of a simple pendulum is given by $T = 2\pi \sqrt{\frac{l}{g_{eff}}}$.Initially,the effective acceleration due to gravity is $g = 9.8 \ m/s^2$,so $t = 2\pi \sqrt{\frac{l}{9.8}}$.When the lift moves upwards with an acceleration $a = 3 \ m/s^2$,the effective acceleration becomes $g' = g + a = 9.8 + 3 = 12.8 \ m/s^2$.The new time period $t'$ is $t' = 2\pi \sqrt{\frac{l}{12.8}}$.Dividing the two equations: $\frac{t'}{t} = \frac{2\pi \sqrt{l/12.8}}{2\pi \sqrt{l/9.8}} = \sqrt{\frac{9.8}{12.8}}$.Therefore,$t' = t \sqrt{\frac{9.8}{12.8}}$.

$A$ simple pendulum has a time period $t$. Its time period in a lift which is moving upwards with an acceleration of $3 \ m/s^2$ is:

Similar Questions

Two simple pendulums of length $1\, m$ and $4\, m$ respectively are both given small displacement in the same direction at the same instant. They will be again in phase after the shorter pendulum has completed a number of oscillations equal to

In $S.H.M.$,a simple pendulum oscillates with frequency $f$. If the length of the pendulum is increased by three times its original length,then the frequency of oscillation of the pendulum will be

$A$ second's pendulum is mounted in a rocket. Its period of oscillation decreases when the rocket

The bob of a simple pendulum is a spherical hollow ball filled with water. $A$ plugged hole near the bottom of the oscillating bob gets suddenly unplugged. During observation,till water is coming out,the time period of oscillation would:

The ratio of frequencies of two pendulums is $2 : 3$. What is the ratio of their lengths?

Vedclass Test Series

Exam Paper Generator

Online Exam Module