A short electric dipole has a dipole moment o | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The electric potential $V$ due to a short electric dipole at a point $(r, 	heta)$ is given by the formula:$V = \frac{1}{4 \pi \epsilon_{0}} \frac

Vedclass · Accepted Answer

$200$

Vedclass · Answer

(C) The electric potential $V$ due to a short electric dipole at a point $(r, 	heta)$ is given by the formula:$V = \frac{1}{4 \pi \epsilon_{0}} \frac{p \cos 	heta}{r^{2}}$Given values:Dipole moment $p = 16 	imes 10^{-9} \, Cm$Distance $r = 0.6 \, m$Angle $	heta = 60^{\circ}$Constant $k = \frac{1}{4 \pi \epsilon_{0}} = 9 	imes 10^{9} \, Nm^{2}/C^{2}$Substituting the values into the formula:$V = \frac{9 	imes 10^{9} 	imes 16 	imes 10^{-9} 	imes \cos(60^{\circ})}{(0.6)^{2}}$Since $\cos(60^{\circ}) = 0.5$:$V = \frac{9 	imes 16 	imes 0.5}{0.36}$$V = \frac{72}{0.36}$$V = 200 \, V$

Similar Questions

Three charges $Q$,$+q$,and $+q$ are placed at the vertices of a right-angled triangle as shown. The net electrostatic potential energy of the configuration is zero. The value of $Q$ is

Three charges $Q, (+q)$ and $(+q)$ are placed at the vertices of an equilateral triangle of side $l$ as shown in the figure. If the net electrostatic potential energy of the system is zero,then $Q$ is equal to

An electric dipole of moment $\vec{p}$ is lying along a uniform electric field $\vec{E}$. The work done in rotating the dipole by $90^{\circ}$ is

Two charges $7 \ \mu C$ and $-4 \ \mu C$ are placed at $(-7 \ cm, 0, 0)$ and $(7 \ cm, 0, 0)$ respectively. Given $\varepsilon_0 = 8.85 \times 10^{-12} \ C^2 \ N^{-1} \ m^{-2}$,the electrostatic potential energy of the charge configuration is: (in $J$)

The condition for minimum potential energy of an electric dipole in a uniform electric field is ......

Vedclass Test Series

Exam Paper Generator

Online Exam Module