A shopkeeper marks the prices of his goods at | vedclass

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(B) Let the original price of the goods be $100$.Since the shopkeeper marks the price $25 \%$ higher,the marked price becomes $100 + 25 = 125$.He allo

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$10 \%$ profit

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(B) Let the original price of the goods be $100$.Since the shopkeeper marks the price $25 \%$ higher,the marked price becomes $100 + 25 = 125$.He allows a discount of $12 \%$ on the marked price.Discount amount $= 12 \% 	ext{ of } 125 = \frac{12}{100} 	imes 125 = 15$.Selling price $= 	ext{Marked price} - 	ext{Discount} = 125 - 15 = 110$.Since the selling price $(110)$ is greater than the original price $(100)$,there is a profit.Profit percentage $= \frac{	ext{Selling price} - 	ext{Original price}}{	ext{Original price}} 	imes 100 = \frac{110 - 100}{100} 	imes 100 = 10 \%$.Alternatively,using the net percentage change formula: $	ext{Net change} = x + y + \frac{xy}{100}$,where $x = 25$ and $y = -12$.Net change $= 25 - 12 + \frac{25 	imes (-12)}{100} = 13 - 3 = 10 \%$.Since the result is positive,it is a $10 \%$ profit.

$A$ shopkeeper marks the prices of his goods at $25 \%$ higher than the original price. After that,he allows a discount of $12 \%$. What profit or loss did he make?

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