A sex-linked recessive gene c produces red-gr | vedclass

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(B) The woman is normal but her father was colourblind, meaning she inherited the recessive gene from him. Thus, her genotype is $X^cX$. The man is co

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(B) The woman is normal but her father was colourblind, meaning she inherited the recessive gene from him. Thus, her genotype is $X^cX$. The man is colourblind, so his genotype is $X^cY$. When we cross $X^cX$ (carrier woman) with $X^cY$ (colourblind man): - The possible genotypes for the offspring are $X^cX^c$ (colourblind girl), $X^cX$ (carrier girl), $X^cY$ (colourblind boy), and $XY$ (normal boy). - Among the girls, $50\%$ are colourblind $(X^cX^c)$ and $50\%$ are carriers $(X^cX)$. Therefore, $50\%$ of the girls are expected to be colourblind.

$A$ sex-linked recessive gene $c$ produces red-green colour blindness in humans. $A$ normal woman whose father was colourblind marries a colourblind man. Of all the girls born to these parents, what percentage is expected to be colourblind?

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