A series combination of two resistors 1,Omega | vedclass

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(B) The total resistance of the circuit in series is $R_{eq} = R_1 + R_2 = 1\,\Omega + 1\,\Omega = 2\,\Omega$.The total resistance including the inter

Vedclass · Accepted Answer

$5$

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(B) The total resistance of the circuit in series is $R_{eq} = R_1 + R_2 = 1\,\Omega + 1\,\Omega = 2\,\Omega$.The total resistance including the internal resistance $r$ of the battery is $R_{total} = R_{eq} + r = 2\,\Omega + 0.4\,\Omega = 2.4\,\Omega$.Using Ohm's law,the current $I$ flowing through the circuit is given by $I = \frac{V}{R_{total}}$.Substituting the values,$I = \frac{12\,V}{2.4\,\Omega} = 5\,A$.Therefore,the correct option is $B$.

$A$ series combination of two resistors $1\,\Omega$ each is connected to a $12\,V$ battery of internal resistance $0.4\,\Omega$. The current flowing through the circuit will be ............... $A$.

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