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(B) The resolving power $(RP)$ of a compound microscope is given by the formula: $RP = \frac{2 \mu \sin 	heta}{1.22 \lambda}$,where $\mu$ is the refr

Vedclass · Accepted Answer

Increase the refractive index of the medium between the object and objective lens.

Vedclass · Answer

(B) The resolving power $(RP)$ of a compound microscope is given by the formula: $RP = \frac{2 \mu \sin 	heta}{1.22 \lambda}$,where $\mu$ is the refractive index of the medium between the object and the objective lens,$	heta$ is the half-angle of the cone of light from the object,and $\lambda$ is the wavelength of light used.To improve the resolving power,one must increase the numerator $(2 \mu \sin 	heta)$ or decrease the denominator $(1.22 \lambda)$.Increasing the refractive index $(\mu)$ of the medium (e.g.,using oil immersion) directly increases the resolving power. Therefore,option $B$ is the correct choice.

$A$ scientist is observing a bacteria through a compound microscope. For better analysis and to improve its resolving power,he should: (Select the best option)

Similar Questions

In a compound microscope,the objective lens and eyepiece have focal lengths of $0.95 \ cm$ and $5 \ cm$ respectively,and are kept at a distance of $20 \ cm$. The final image is formed at a distance of $25 \ cm$ from the eyepiece. Calculate the magnifying power.

What are the objective and the eye-piece in an optical instrument?

The near vision of an average person is $25 \, cm$. To view an object with an angular magnification of $10$,what should be the power of the microscope?

The magnifying power of a simple microscope can be increased if we use an eyepiece of:

In order to increase the magnifying power of a compound microscope:

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