A room is 7 text{ m} long and 5 text{ m} broa | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(NONE) Let the height of the room be $h 	ext{ m}$.
Area of the four walls $= 2(l + b) 	imes h = 2(7 + 5) 	imes h = 24h 	ext{ m}^2$.
Area to be p

Vedclass · Accepted Answer

$400$

Vedclass · Answer

(NONE) Let the height of the room be $h 	ext{ m}$.
Area of the four walls $= 2(l + b) 	imes h = 2(7 + 5) 	imes h = 24h 	ext{ m}^2$.
Area to be papered $= (24h - 5) 	ext{ m}^2$.
Width of paper $= 75 	ext{ cm} = 0.75 	ext{ m}$.
Length of one piece of paper $= 13 	ext{ m}$.
Area of one piece of paper $= 13 	imes 0.75 = 9.75 	ext{ m}^2$.
Cost of one piece $= ₹ 4.20$.
Total cost $= ₹ 39.20$.
Number of pieces required $= \frac{39.20}{4.20} = \frac{392}{42} = \frac{28}{3} 	ext{ pieces}$.
Total area of paper $= \frac{28}{3} 	imes 9.75 = 28 	imes 3.25 = 91 	ext{ m}^2$.
Equating the areas: $24h - 5 = 91$.
$24h = 96$.
$h = 4 	ext{ m}$.
Since $1 	ext{ m} = 100 	ext{ cm}$,the height is $400 	ext{ cm}$.

$A$ room is $7 \text{ m}$ long and $5 \text{ m}$ broad. The doors and windows occupy $5 \text{ m}^2$. The cost of papering the remaining part of the walls with paper $75 \text{ cm}$ wide,at ₹ $4.20$ per piece of $13 \text{ m}$ length,is ₹ $39.20$. Find the height of the room in $\text{cm}$.

Similar Questions

What will be the area of a circle with circumference equal to $88\, cm$? (in $Sq\, cm$)

The ratio of the $3$ angles of a quadrilateral is $13: 9: 5$. The value of the $4^{th}$ angle of the quadrilateral is $36^{\circ}$. What is the difference between the largest and the second smallest angles of the quadrilateral? (in $^{\circ}$)

The area of a big rectangle is equal to the area of a small rectangle. If the length of the big rectangle is equal to the length of the small rectangle and the width of the big rectangle is $2 \ m$,what is the width of the small rectangle?

In trapezium $ABCD$,$AB || CD$ and $AB = 2 \, CD$. Its diagonals intersect at $O$. If the area of $\Delta AOB = 84 \, cm^2$,then the area of $\Delta COD$ is equal to (in $cm^2$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module