A room is 7 text{ m} long and 5 text{ m} broa | vedclass

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(B) Let the height of the room be $h 	ext{ m}$.Area of the four walls $= 2 	imes (7 + 5) 	imes h = 24h 	ext{ m}^2$.Area to be papered $= (24h - 5)

Vedclass · Accepted Answer

$4$

Vedclass · Answer

(B) Let the height of the room be $h 	ext{ m}$.Area of the four walls $= 2 	imes (7 + 5) 	imes h = 24h 	ext{ m}^2$.Area to be papered $= (24h - 5) 	ext{ m}^2$.Width of paper $= 75 	ext{ cm} = 0.75 	ext{ m}$.Area of one piece of paper $= 13 	ext{ m} 	imes 0.75 	ext{ m} = 9.75 	ext{ m}^2$.Number of pieces required $= \frac{24h - 5}{9.75}$.Cost of one piece $= ₹ 4.20$.Total cost $= \frac{24h - 5}{9.75} 	imes 4.20 = 39.20$.$\frac{24h - 5}{9.75} = \frac{39.20}{4.20} = \frac{392}{42} = \frac{28}{3}$.$3(24h - 5) = 28 	imes 9.75$.$72h - 15 = 273$.$72h = 288$.$h = 4 	ext{ m}$.

$A$ room is $7 \text{ m}$ long and $5 \text{ m}$ broad. The doors and windows occupy $5 \text{ m}^2$. The cost of papering the remaining part of the walls with paper $75 \text{ cm}$ wide,at ₹ $4.20$ per piece of $13 \text{ m}$,is ₹ $39.20$. Find the height of the room (in $\text{m}$).

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