A roller is 120 , cm long and has a diameter | vedclass

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(D) Given: Length of the roller $(h)$ = $120 \, cm = 1.2 \, m$. Diameter of the roller = $84 \, cm$,so radius $(r)$ = $42 \, cm = 0.42 \, m$. The area

Vedclass · Accepted Answer

$475.20$

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(D) Given: Length of the roller $(h)$ = $120 \, cm = 1.2 \, m$. Diameter of the roller = $84 \, cm$,so radius $(r)$ = $42 \, cm = 0.42 \, m$. The area levelled in one revolution is equal to the curved surface area of the cylinder: $CSA = 2 \pi r h = 2 	imes \frac{22}{7} 	imes 0.42 	imes 1.2 \, m^2$. $CSA = 2 	imes 22 	imes 0.06 	imes 1.2 = 3.168 \, m^2$. Total area levelled in $500$ revolutions = $500 	imes 3.168 = 1584 \, m^2$. Cost of levelling = $1584 	imes 30 \, 	ext{paise} = 47520 \, 	ext{paise}$. Converting to Rupees: $47520 / 100 = Rs. 475.20$.

$A$ roller is $120 \, cm$ long and has a diameter of $84 \, cm$. If it takes $500$ complete revolutions to level a playground,determine the cost of levelling at the rate of $30 \, \text{paise}$ per $m^2$ (in $Rs.$). (Use $\pi = \frac{22}{7}$)

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