(B) Volume of the rod $V = 10 \times 0.5 \times 0.2 \, cm^3 = 1 \, cm^3 = 10^{-6} \, m^3$.Given magnetic field strength $H = 0.5 \times 10^4 \, Am^{-1

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(B) Volume of the rod $V = 10 \times 0.5 \times 0.2 \, cm^3 = 1 \, cm^3 = 10^{-6} \, m^3$.Given magnetic field strength $H = 0.5 \times 10^4 \, Am^{-1}$ and magnetic moment $M = 5 \, Am^2$.Intensity of magnetization $I = \frac{M}{V} = \frac{5}{10^{-6}} = 5 \times 10^6 \, Am^{-1}$.Magnetic induction $B$ is given by $B = \mu_0(I + H)$.Since $I \gg H$,we have $B \approx \mu_0 I$.$B = 4\pi \times 10^{-7} \times 5 \times 10^6 = 20\pi \times 10^{-1} = 2\pi \approx 6.28 \, T$.

Class 12 Physics Magnetism and Matter Magnetization, Magnetic Induction Susceptibility

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$A$ rod of ferromagnetic material with dimensions $10 \, cm \times 0.5 \, cm \times 0.2 \, cm$ is placed in a magnetic field of strength $0.5 \times 10^4 \, Am^{-1}$. As a result,a magnetic moment of $5 \, Am^2$ is produced in the rod. The value of magnetic induction will be.... $T$

A
$0.54$
B
$6.28$
C
$0.358$
D
$2.591$

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Class 12

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Magnetism and Matter

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Magnetization, Magnetic Induction Susceptibility

The magnetic susceptibility of the material of a rod is $499$. Permeability of vacuum is $4 \pi \times 10^{-7} \ H/m$. The absolute permeability of the material of the rod in $H/m$ is:

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The magnetic susceptibility is defined as:

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$A$ solenoid of $500$ turns $/ m$ is carrying a current of $3 \ A$. Its core is made of iron which has a relative permeability of $5001$. The magnitude of magnetization is:

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The relation between $\mu$ and $H$ for a specimen of iron is $\mu = [\frac{0.4}{H} + 12 \times 10^{-4}] \ H m^{-1}$. The value of $H$ which produces a flux density of $1 \ T$ will be ($\mu =$ magnetic permeability,$H =$ magnetic intensity).

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If $M$ is the magnetisation induced in the material,$H$ is the magnetic field intensity,and $B$ is the net magnetic field inside the material,then the correct relation between them is $(\mu_0 = \text{permeability of free space})$

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$A$ rod of ferromagnetic material with dimensions $10 \, cm \times 0.5 \, cm \times 0.2 \, cm$ is placed in a magnetic field of strength $0.5 \times 10^4 \, Am^{-1}$. As a result,a magnetic moment of $5 \, Am^2$ is produced in the rod. The value of magnetic induction will be.... $T$

Similar Questions

The magnetic susceptibility of the material of a rod is $499$. Permeability of vacuum is $4 \pi \times 10^{-7} \ H/m$. The absolute permeability of the material of the rod in $H/m$ is:

The magnetic susceptibility is defined as:

$A$ solenoid of $500$ turns $/ m$ is carrying a current of $3 \ A$. Its core is made of iron which has a relative permeability of $5001$. The magnitude of magnetization is:

The relation between $\mu$ and $H$ for a specimen of iron is $\mu = [\frac{0.4}{H} + 12 \times 10^{-4}] \ H m^{-1}$. The value of $H$ which produces a flux density of $1 \ T$ will be ($\mu =$ magnetic permeability,$H =$ magnetic intensity).

If $M$ is the magnetisation induced in the material,$H$ is the magnetic field intensity,and $B$ is the net magnetic field inside the material,then the correct relation between them is $(\mu_0 = \text{permeability of free space})$

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