A rod P of length 1 m is hinged at one end A | vedclass

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(B) Let the distance between hinges $A$ and $B$ be $l$. From the geometry of the system,the position of the ring at any angle $	heta$ can be describe

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$2$

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(B) Let the distance between hinges $A$ and $B$ be $l$. From the geometry of the system,the position of the ring at any angle $	heta$ can be described. When the angle $\phi$ is maximum,the rod $Q$ becomes tangent to the circular path traced by the ring attached to rod $P$. At this point,the angle $	heta$ is $60^{\circ}$. In this configuration,the rod $P$ (of length $1 \ m$) forms a right-angled triangle with the line segment $AB$ and the tangent rod $Q$. Using trigonometry in this triangle,we have $1 = l \cos(60^{\circ})$. Since $\cos(60^{\circ}) = 0.5$,we get $1 = l 	imes 0.5$. Therefore,$l = 2 \ m$.

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