A rocket is moving up with a velocity v. If t | vedclass

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(B) The formula for kinetic energy $(K.E)$ is given by $K.E = \frac{1}{2}mv^2$,where $m$ is the mass and $v$ is the velocity.Let the initial velocity

Vedclass · Accepted Answer

$1:9$

Vedclass · Answer

(B) The formula for kinetic energy $(K.E)$ is given by $K.E = \frac{1}{2}mv^2$,where $m$ is the mass and $v$ is the velocity.Let the initial velocity be $v_1 = v$. The initial kinetic energy is $K_1 = \frac{1}{2}mv^2$.When the velocity is tripled,the new velocity becomes $v_2 = 3v$.The final kinetic energy is $K_2 = \frac{1}{2}m(3v)^2 = \frac{1}{2}m(9v^2) = 9 	imes (\frac{1}{2}mv^2)$.Therefore,the ratio of the initial kinetic energy to the final kinetic energy is $K_1 : K_2 = \frac{1}{2}mv^2 : 9(\frac{1}{2}mv^2) = 1:9$.

$A$ rocket is moving up with a velocity $v$. If the velocity of this rocket is suddenly tripled,what will be the ratio of the initial kinetic energy to the final kinetic energy?

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