A ring of mass m and radius r rotates about a | vedclass

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(A) The rotational kinetic energy $(K)$ of a rigid body rotating about a fixed axis is given by the formula $K = \frac{1}{2} I \omega^{2}$,where $I$ i

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$\frac{1}{2} m r^{2} \omega^{2}$

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(A) The rotational kinetic energy $(K)$ of a rigid body rotating about a fixed axis is given by the formula $K = \frac{1}{2} I \omega^{2}$,where $I$ is the moment of inertia and $\omega$ is the angular velocity.For a ring of mass $m$ and radius $r$ rotating about an axis passing through its centre and perpendicular to its plane,the moment of inertia is $I = m r^{2}$.Substituting the value of $I$ into the kinetic energy formula:$K = \frac{1}{2} (m r^{2}) \omega^{2} = \frac{1}{2} m r^{2} \omega^{2}$.

$A$ ring of mass $m$ and radius $r$ rotates about an axis passing through its centre and perpendicular to its plane with angular velocity $\omega$. Its kinetic energy is

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