A right triangle with sides 6 , cm,8 , cm,and | vedclass

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Question

(D) When a right triangle is revolved about one of its sides (containing the right angle),a cone is formed.Here,the side about which the triangle is r

Vedclass · Accepted Answer

$188.57$

Vedclass · Answer

(D) When a right triangle is revolved about one of its sides (containing the right angle),a cone is formed.Here,the side about which the triangle is revolved becomes the height $(h)$ of the cone,and the other side becomes the radius $(r)$ of the base.Given:Height $(h) = 8 \, cm$Radius $(r) = 6 \, cm$Slant height $(l) = 10 \, cm$The curved surface area of a cone is given by the formula: $	ext{CSA} = \pi r l$Substituting the values:$	ext{CSA} = \frac{22}{7} 	imes 6 	imes 10$$	ext{CSA} = \frac{1320}{7} \approx 188.57 \, cm^2$Thus,the curved surface area of the solid formed is $188.57 \, cm^2$.

$A$ right triangle with sides $6 \, cm$,$8 \, cm$,and $10 \, cm$ is revolved about the side $8 \, cm$. Find the curved surface area of the solid so formed (in $cm^2$). (in $, cm^2$)

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