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(D) First,calculate the semi-perimeter $(s)$ of the triangular base:$s = \frac{a + b + c}{2} = \frac{13 + 20 + 21}{2} = \frac{54}{2} = 27\, cm$Next,ca

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(D) First,calculate the semi-perimeter $(s)$ of the triangular base:$s = \frac{a + b + c}{2} = \frac{13 + 20 + 21}{2} = \frac{54}{2} = 27\, cm$Next,calculate the area of the triangular base using Heron's formula:$	ext{Area} = \sqrt{s(s - a)(s - b)(s - c)}$$= \sqrt{27(27 - 13)(27 - 20)(27 - 21)}$$= \sqrt{27 	imes 14 	imes 7 	imes 6}$$= \sqrt{15876} = 126\, cm^2$The volume of a right prism is given by the product of the base area and the altitude (height):$	ext{Volume} = 	ext{Base Area} 	imes 	ext{Height}$$= 126\, cm^2 	imes 9\, cm = 1134\, cm^3$

$A$ right prism has a triangular base whose sides are $13\, cm, 20\, cm$ and $21\, cm$. If the altitude of the prism is $9\, cm$,then its volume is......$cm^3$

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