A resistor develops 300 ,J of thermal energy | vedclass

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(B) The thermal energy $H$ developed in a resistor is given by the formula $H = i^2 Rt$,where $i$ is the current,$R$ is the resistance,and $t$ is the

Vedclass · Accepted Answer

$450$

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(B) The thermal energy $H$ developed in a resistor is given by the formula $H = i^2 Rt$,where $i$ is the current,$R$ is the resistance,and $t$ is the time.First,we find the resistance $R$ using the given values: $H = 300 \,J$,$i = 2 \,A$,and $t = 15 \,s$.$300 = 2^2 	imes R 	imes 15$$300 = 4 	imes R 	imes 15$$300 = 60R$$R = \frac{300}{60} = 5 \,\Omega$Now,we calculate the energy developed when the current $i = 3 \,A$ and time $t = 10 \,s$ with the same resistance $R = 5 \,\Omega$:$H = i^2 Rt$$H = 3^2 	imes 5 	imes 10$$H = 9 	imes 5 	imes 10$$H = 450 \,J$

$A$ resistor develops $300 \,J$ of thermal energy in $15 \,s$,when a current of $2 \,A$ is passed through it. If the current increases to $3 \,A$,the energy developed in $10 \,s$ is........$J.$

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