$A$ rectangular coil of $300$ turns has an average area of $25\;cm \times 10\;cm.$ The coil rotates with a speed of $50\;cps$ in a uniform magnetic field of strength $4 \times 10^{-2}\;T$ about an axis perpendicular to the field. The peak value of the induced $e.m.f.$ is (in volt): (in $\pi$)

When a wire loop is rotated in a magnetic field,the direction of induced $emf$ changes in every

$A$ circular coil of radius $8.0 \, cm$ and $20$ turns is rotated about its vertical diameter with an angular speed of $50 \, rad \, s^{-1}$ in a uniform horizontal magnetic field of $3.0 \times 10^{-2} \, T$. The maximum $emf$ induced in the coil will be $\ldots \ldots \ldots \times 10^{-2} \, V$ (rounded off to the nearest integer).

$A$ circular coil of resistance $R$,area $A$,and number of turns $N$ is rotated about its vertical diameter with angular speed $\omega$ in a uniform magnetic field of magnitude $B$. The average power dissipated in a complete cycle is:

$A$ ring of resistance $10 \ \Omega$,radius $10 \ cm$ and $100$ turns is rotated at a rate of $100$ revolutions per second about its diameter perpendicular to a uniform magnetic field of induction $10 \ mT$. The amplitude of the current in the loop will be nearly $....... \ A$. (Take: $\pi^2 = 10$)

What is the phase difference between the flux linked with a coil rotating in a magnetic field and the induced emf produced in it?