$A$ reaction rate constant is given by $k = 1.2 \times 10^{14} e^{-(25000/RT)} \, s^{-1}$. It means

• A
  $\log k$ versus $\log T$ will give a straight line with slope as $-25000$
• B
  $\log k$ versus $T$ will give a straight line with slope as $-25000$
• C
  $\log k$ versus $\log 1/T$ will give a straight line with slope as $-25000$
• D
  $\log k$ versus $1/T$ will give a straight line