A reaction rate constant is given by k = 1.2 | vedclass

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(D) The Arrhenius equation is given by $k = A \, e^{-E_a/RT}$.Taking the natural logarithm on both sides: $\ln \, k = \ln \, A - \frac{E_a}{RT}$.Conve

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$\log \, k$ versus $1/T$ will give a straight line

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(D) The Arrhenius equation is given by $k = A \, e^{-E_a/RT}$.Taking the natural logarithm on both sides: $\ln \, k = \ln \, A - \frac{E_a}{RT}$.Converting to base $10$ logarithm: $\log \, k = \log \, A - \frac{E_a}{2.303 \, R} 	imes \frac{1}{T}$.Comparing this with the equation of a straight line $y = mx + c$,where $y = \log \, k$ and $x = \frac{1}{T}$,the slope $m = -\frac{E_a}{2.303 \, R}$.Therefore,a plot of $\log \, k$ versus $\frac{1}{T}$ yields a straight line.

$A$ reaction rate constant is given by $k = 1.2 \times 10^{14} \, e^{-25000/RT} \, sec^{-1}$. It means

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