A reaction between CH_3MgBr (methyl magnesium | vedclass

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Question

(A) Grignard reagents $(RMgX)$ are strong bases and react with compounds containing active hydrogen atoms (like alcohols,water,or amines) to form alka

Vedclass · Accepted Answer

Methane

Vedclass · Answer

(A) Grignard reagents $(RMgX)$ are strong bases and react with compounds containing active hydrogen atoms (like alcohols,water,or amines) to form alkanes.The reaction is as follows:$C_2H_5OH + CH_3MgBr \rightarrow CH_4 + Mg(OC_2H_5)Br$Here,the $CH_3^-$ group from the Grignard reagent abstracts the acidic proton $(H^+)$ from the ethyl alcohol $(C_2H_5OH)$ to form methane $(CH_4)$.

$A$ reaction between $CH_3MgBr$ (methyl magnesium bromide) and $C_2H_5OH$ (ethyl alcohol) gives:

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